Math, asked by abhisheknaik2k18, 1 year ago

Divide x^3+x^2+x+46 if x=2+3i

Answers

Answered by harinimarippan2003
4

Answer:

-5 +24i

Step-by-step explanation:

substitute x's value in x³ + x² + x +46

therefore we get,

                         (2+3i)³ + (2+3i)² + (2+3i) + 46

=  [(2)³ + (3i)³ + 3(2)(3i)(2+3i)] + [ (2)² + (3i)² + 2(2)(3i) ] + (2+3i) + 46

=  [ 8-27i+18i(2+3i) ] + [ 2-9+12i] + (2+3i) + 46

= (8-27i+36i-54) + (-7+12i) + (2+3i) + 46

= 9i -46 -7 +12i +2 +3i +46

= -5 + 24i

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