Math, asked by bunny190, 1 year ago

divide x(3x²-108)by3x(x-6)

Answers

Answered by atul103
15
Here is your solution

X(3x^2-108) /3x(x-6)
==========================
==>
3x(x^2-36) /3x (x-6)
Now 3x/3x is canceled

=(X^2 - 6^2) / (x-6)

= (x-6) (x+6) / x-6

==> (X+6) answer
Answered by Prabhatsingh12
6
x( 3x^2 - 108) ÷ 3x(x-6).
3x^3 - 108x ÷ 3x^2 - 18x .
3x^2 - 18x ) 3x^3 -108x ( x - 6
3x^3 -18^2
-108x - 18^2
-108x - 18x^2
00 00
Quotient = x -6.
Hope this answer will help you and plz mark it as brainliest.
Similar questions