Math, asked by Meghana1223, 3 months ago

divide x^4+2x+3x^3+1 by 2x+x^2​

Answers

Answered by rkcomp31
1

Answer:

Step-by-step explanation:

x^4+3x^3+2x+1\\\\=x^4+2x^3+x^3+2x^2-2x^2-4x+6x+1\\\\=x^2(x^2+2x)+x(x^2+2x)-2(x^2+2x)+ (6x+1)\\\\\bf=(x^2+2x)(x^2+x-2)+6x+1\\\\Thus\\\\Quotient=\ x^2+x-2 \ and \ remainder \ = 6x+1

Answered by Ankur12123
1

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