divide x^6-1 by x^3+1
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Let the age of father be x years
Let the age of one of his children be y years and age of other children be z years
From given information,
x=2×(y+z)...(1)
After 20 years,
(x+20)=(y+20)+(z+20)...(2)
Substituting value of (1) in (2), we get
2×(y+z) +20=y+z+40
2y+2z−y−z=40−20
y+z=20...(3)
Substituting value of (3) in (1), we get
x=2×(20)
⇒x=40
Answered by
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Answer:
1) Multiply (x
3
−2x
2
+2x−1)with x
3
, to get x
6
, Remainder =2x
5
−2x
4
+x
3
−1
2) Multiply (x
3
−2x
2
+2x−1)with 2x
2
, to get 2x
5
, Remainder =2x
4
−3x
3
+2x
2
−1
3)Multiply (x
3
−2x
2
+2x−1)with 2x to get 2x
4
, Remainder =x
3
−2x
2
+2x−1
4) Multiply (x
3
−2x
2
+2x−1)with 1, to get x
3
−2x
2
+2x−1, remainder =0
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