Math, asked by aritradarkarceus, 1 month ago

divide x^6-y^6 by x-y and then again divide the result by x²+xy+y².​

Answers

Answered by yugansh5201
0

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Answered by bagkakali
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Answer:

x^6-y^6

=(x^3)^2-(y^3)^2

=(x^3+y^3)(x^3-y^3)

=(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2)

1st we divide it by (x-y) ,we get

(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2)÷(x-y)

=(x+y)(x^2-xy+y^2)(x^2+xy+y^2)

now we divide it by (x^2+xy+y^2)

(x+y)(x^2-xy+y^2)(x^2+xy+y^2)÷(x^2+xy+y^2)

=(x+y)(x^2-xy+y^2)

=(x^3-y^3)

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