divide x^6-y^6 by x-y and then again divide the result by x²+xy+y².
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Answer:
x^6-y^6
=(x^3)^2-(y^3)^2
=(x^3+y^3)(x^3-y^3)
=(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2)
1st we divide it by (x-y) ,we get
(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2)÷(x-y)
=(x+y)(x^2-xy+y^2)(x^2+xy+y^2)
now we divide it by (x^2+xy+y^2)
(x+y)(x^2-xy+y^2)(x^2+xy+y^2)÷(x^2+xy+y^2)
=(x+y)(x^2-xy+y^2)
=(x^3-y^3)
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