divide (x^6-y^6) by (x-y)
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Answered by
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Answer:
The following identities are true for every real
a
,
b
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
a
3
+
b
3
=
(
a
+
b
)
(
a
2
−
a
b
+
b
2
)
Hence
x
6
−
y
6
=
=
(
x
3
)
2
−
(
y
3
)
2
=
(
x
3
+
y
3
)
(
x
3
−
y
3
)
=
(
x
+
y
)
(
x
2
−
x
y
+
y
2
)
(
x
−
y
)
(
x
2
+
x
y
+
y
2
)
from the last equation we have that
x
6
−
y
6
=
(
x
+
y
)
(
x
2
−
x
y
+
y
2
)
(
x
−
y
)
(
x
2
+
x
y
+
y
2
)
⇒
x
6
−
y
6
x
−
y
=
(
x
+
y
)
⋅
(
x
2
−
x
y
+
y
2
)
(
x
2
+
x
y
+
y
2
)
Step-by-step explanation:
I hope its help to you
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