Question

divide (x+6x²-15) by (2x-3)
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Answer 1

Using Remainder Theorem,

g(x)=0

2x-3=0

x=3/2

Putting x= 3/2 in p(x)=x+6x²-15

3/2+6(3/2)²-15

3/2+6×3/2×3/2-15

3/2+27/2-15

30/2-15

15-15

0.

Answer 2

Question -:

Divide

(6x² + x - 15) by (2x - 3)

Explanation -:

$\small\sf{(6 {x}^{2} + x - 15)by \: (2x - 3) }$

$\begin{array}{cc} \small \: \rm \: 2x - 3) \: 6 {x }^{2} + x- 15(3x + 5 \\ \small \rm \underline{6 {x }^{2} - 9x} \\ \small\rm10x - 15 \\ \small\rm \: \underline{10x - 15} \\ \small0 \end{array}$