Question

divide x cube minus 3 x square - 9 x minus 5 by X + 1​

Answer 1

x^3-3x^2-9x-5

Answer:

let x+1=0

x=0-1

x=-1

put x=-1

=(-1)^3-3(-1)^2-9(-1)-5

= -1-3+9-5

= -9+9

= 0

remainder is 0...

i hope it is helpful to u...