Question

divide x cube minus 4 x square + X + 6 by x minus 3 using division method​

Answer 1

$= \frac{ {x}^{3} - 4 {x}^{2} + x + 6 }{x - 3} \\ = \frac{ {x}^{3} - 3 {x}^{2} - {x}^{2} + 3x - 2x + 6}{x - 3} \\ divide \: the \: term \: x - 3 \: and \: cancel \: \\ it \: out \: \\ = \frac{ {x}^{2}( x - 3) - x(x - 3) - 2(x - 3) }{x - 3 } \\ = {x}^{2} - x - 2 \\ hope \: it \:helps \: u \:$