Math, asked by brisr5775, 5 hours ago

Divide (x²+2x-8) entre (x-1)​

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Answered by XxIndianpilotxX
1

divide \:  (x²+2x-8)  (x-1) \\  \\  ans. \:  \: x - 1 \sqrt{x² + 2x - 8}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x(x - 1) = x² - x   \\ x² - x  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  x² \: is \: now \: cutted \: because \:that \: common \: and \: \\  subract \: 2x \: into \: x \\  \\  \sqrt{x - 8}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 1(x - 1) = x - 1 \\   x - 1  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\ we \: subtract \: x - 8 \: into \: x - 1 \\  \\  \\ so \: our \: remainder \: is \: 7 \: and \: quotient \: is \: x + 1answer.

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