Question

divide x2-3 by x4+x3-23x2-3x+60​

Answer 1

Step-by-step explanation:

on dividing x^4+x^3-23x^2-3x+60 by 2x^2+0x-3 we get q(x)=x^2+x-20 and r(x)=00

Answer 2

Answer:

(x - root3)*(x + root3) is one factor

By using identity

(x^2 - 3) is one factor

x^4 + x^3 - 23x^2 - 3x + 60 / x^2 - 3

= x^2 + x - 20

The zeroes of x^2 + x - 20 are -5 and 4

All the zeroes of the given polynomial are

root3, -root3, -5, 4