Question

divide x²-4x+4by x-2

Answer 1

Hi there !!

Given,

To divide x² - 4x + 4 ÷ x - 2

$= \frac{ {x}^{2} - 4x + 4 }{x - 2}$
It can be seen that in x² - 4x + 4 ,
the 2nd identity that is, (x - y)² = x² - 2xy + y²

So,

$= \frac{(x) {}^{2} - 2(x)(2) + (2) {}^{2} }{x - 2}$

$= \frac{(x - 2) {}^{2} }{x - 2}$

$= \frac{(x - 2)(x - 2)}{(x - 2)}$
cancelling x-2 and x-2 in the numerator and denominator,
we have,

(x - 2)

Thus,
the answer is (x-2)

Answer 2

HELLO DEAR,


X-2 ) X²-4X+4( X - 2
X² -2x
(-) (+)
-----------------
0 - 2x +4
-2x +4
---—-----——
0 + 0


hence ,

the divisible of (x²-4x+4)/(x-2)

=> (x-2)





-----------------OR-----------------

ANOTHER METHOD


X² - 4X +4 / (X-2)

=> (X² - 2X - 2X +4) / (X-2)

=> [ X(X-2) - 2(X-2)] / (X-2)

=> [(X-2)(X-2)] / (X-2)

=> (X-2)



I HOPE ITS HELP YOU DEAR,
THANKS