Question

Divide (-x2 + 6x3 – 3 – 10x) by (2x - 3) and find the
quotient and remainder. Also check your answer.​

Answer 1

Answer:

quotient = 3x²+4x +1

remainder = 0

Step-by-step explanation:

-x²+6x³-3-10x

f(x)=6x³-x²-10x-3

g(x)= 2x-3

checking solutions

f(x)=g(x)*q(x)+r(x)

6x³-x²+10x-3 = (2x-3)(3x²+4x+1)+0

= 6x³+8x²+2x-9x²-12x-3

= 6x³-x²-10x-3

.: R.H.S = L.H.S

Answer 2

Answer:

3x^2+4x+1 No remainder

Step-by-step explanation:

I took the time to work this out and I also did this on a test and got it right