Question

divide x2+y2-2xy-9z2 by x-y-3z​

Answer 1

Answer:

ANSWER

We know that, (x+y+z)(x2+y2+z2−xy−yz−zx)=x3+y3+z3−3xyz

∴(x+2y+3z)(x2+4y2+9z2−2xy−6yz−3zx)

=(x+2y+3z)[x2+(2y)2+(3z)2−(x)(2y)−(2y)(3z)−(3z)(x)]

=(x3)+(2y)3+(3z)3−3(x)(2y)(3z)

=x3+8y3+27z3−18xyz