Question

divide (x³+1) by (x+3). (-6y²+29y-28) by (3y-4) ​

Answer 1

Using long division you get

$=x^2-3x+9-\frac{26}{x+3}$

and by factoring the top you can get

$=-\frac{\left(3y-4\right)\left(2y-7\right)}{3y-4}$ cancel out common factor

$=-\left(2y-7\right)$

$=-2y+7$