divide : x³+27 by x+3
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x^3 + 27, YOU CAN WRITE IT AS x^3 + 0x^2 + 0x + 27
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On dividing (x³+27) by (x+3) we will get (x²–3x+9²).
Given:
x³+27 and x+3
To find:
Divide: x³+27 by x+3
Solution:
Given x³+27
As we know 3³ = 27
⇒ x³+27 = (x³+3³)
From Algebraic identities,
(a³ - b³) = (a - b) (a² + ab + b²)
Take a = x and b = 3
⇒ (x³ - 3³) = (x + 3) (x² – x(3) + 3²)
= (x + 3) (x² –3x + 9²)
⇒ (x³+27)/ (x+3)
= (x+3) (x²–3x+9²)/(x+3) = (x²–3x+9²)
Therefore,
On dividing (x³+27) by (x+3) we will get (x²–3x+9²).
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