Question

divide x³– 27x²+8x+18 by factor therom method​

Answer 1

Answer:

o check if (x-1) is a factor of the equation, put x=1 as value of x in the above polynomial....putting x = 1

we get,

= x3-27x2+8x+18

= (1)3-27 (1)2+8 (1)+18

= 1-27+8+18

= 0

If we get zero, then

(x-1) IS A factor of the given polynomial..