divide x3-2x-1 by x2-x-1 then quotient will be
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Answer
Let p(x)=2x
4
+x
3
−14x
2
−19x+6.
Given that the divisor is 2x+1. Write 2x+1=0. Then x=−
2
1
therefore The zero of the divisor is x=−
2
1
.
So, 2x
4
+x
3
−14x
2
−19x+6=(x+
2
1
){2x
3
−14x−12}+12
=(2x+1)
2
1
(2x
3
−14x−12)+12
Thus, the quotient is
2
1
(2x
2
−14x−12)=x
3
−7x−6 and the remainder is 12.
But, given quotient is x
3
+ax
2
−bx−6. Comparing this with the quotient obtained we get, a = 0 and b = 7.
Thus, a=0, b=7 and the remainder is 12.
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