Question

Divide x3+ 2x + 6x - 20
by x-1​

Answer 1

Answer:

Three solutions were found :

 x = 5

 x =(-2-√-12)/2=-1-i√ 3 = -1.0000-1.7321i

 x =(-2+√-12)/2=-1+i√ 3 = -1.0000+1.7321i

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "x2"   was replaced by   "x^2".  1 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

(((x3) - 3x2) - 6x) - 20 = 0

Step  2  :

Checking for a perfect cube :

 2.1    x3-3x2-6x-20  is not a perfect cube

Trying to factor by pulling out :

 2.2      Factoring:  x3-3x2-6x-20 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -6x-20 

Group 2:  -3x2+x3 

Pull out from each group separately :

Group 1:   (3x+10) • (-2)

Group 2:   (x-3) • (x2)

Bad news !! Factoring

Answer 2

Answer:

p(x) = x³+8x-20

g(x) = x-1

x-1 ) x³+8x-20 ( x²-x+7

x³-x²

---------------

-x²+8x-20

-x²+1x

------------------

7x-20

7x-7

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