divide x³+3x²+3x+1 by (x+1)
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Apply remainder theorem
=>x + 1 =0
=> x = - 1
Replace x by � 1 we get
=>x3+3x2 + 3x + 1
=>(-1)3 + 3(-1)2 + 3(-1) + 1
=> -1 + 3 - 3 + 1
=> 0
Remainder is 0
please please please m ark has brainliest answer
Apply remainder theorem
=>x + 1 =0
=> x = - 1
Replace x by � 1 we get
=>x3+3x2 + 3x + 1
=>(-1)3 + 3(-1)2 + 3(-1) + 1
=> -1 + 3 - 3 + 1
=> 0
Remainder is 0
please please please m ark has brainliest answer
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