divide x³+3x²y+3xy²+y³ by x+1
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Answer:
The value of x^3+3x^2y+3xy^2+y^3 by x+1 is
=x^3+3x^2y+3xy^2+y^3/x+1
=(x+1)^3/x+1
=(x+1)^3×(x+1)^-1
=(x+1)^2
=x^2+2x+1
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Step-by-step explanation:
if you take (x+y)then answer is given in 2nd picture
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