Question

divide x3+5x-3x2-3 by x2-2​

Answer 1

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Answer 2

Divide:

Step-by-step explanation:

$\ Given \ value:\\\\\ divisor = x^2-2 \\\\\ dividend = x^3+5x-3x^2-3 \\\\\ Solution:\\\\x^3\ + \ 5x\ -\ 3x^2\ -\ 3 \div x^2-2\\\\\frac{x^3+5x-3x^2-3}{x^2-2}\\\\ \ quotient = x+3\\\\\ remainder= 7x-9$

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