Question

Divide [x³ + 5x² + 5(x+5)² + (x - 16) (x +5)] by (x² + 8x + 15) please answer fast and give step by step explanation

Answer 1

Answer:

On dividing [x³ + 5x² + 5(x+5)² + (x - 16) (x +5)] by (x² + 8x + 15), we will get x - 2 as the divisor and -5 as the remainder

Step-by-step explanation:

[x³ + 5x² + 5(x+5)² + (x - 16) (x +5)] ÷ (x² + 8x + 15)

[x²(x + 5) + 5(x+5)² + (x - 16) (x +5)] ÷ (x² + 5x + 3x + 15)

[x²(x + 5) + 5(x+5)² + (x - 16) (x +5)] ÷ [x(x + 5) + 3(x + 5)]

Taking (x+5) common

=> (x + 5)[x² + 5 + (x - 16)] ÷ (x + 5) (x + 3)

Cancelling (x + 5) as it is common in both the divisor and dividend

=> [x² + 5 + x - 16] ÷  (x + 3)

=> [x²  + x - 11] ÷  (x + 3)

On dividing x²  + x - 11 by x + 3 by long division,

We will get x - 2 as the divisor and -5 as the remainder