Question

divide: x³-6x²+12x-8 by x-2
step by step pls​

Answer 1

☯GIVEN :

• $\bf{p(x) =x^3-6x^2+12x-8}$

• $\bf{g(x) = x-2}$

☯TO FIND :

• Remainder.

➲SOLUTION :

• By Remainder Theorem :

Let us assume g(x) = 0.

$: \longrightarrow{ \tt{x -2= 0}}$

$: \longrightarrow{ \tt{x = 0 +2}}$

$: \longrightarrow{ \bf{x = 2}}$

✞Substituting the value of x :

$:\longrightarrow{\tt{p(x) =x^3-6x^2+12x-8}}$

$: \longrightarrow{\tt{p(2) =(2)^3-6(2)^2+12\times2-8}}$

$: \longrightarrow{\tt{p(2) =8-6\times 4+12\times2-8}}$

$: \longrightarrow{\tt{p(2) = 8-24+24-8}}$

$: \longrightarrow{\tt{p(2) = 8+24-24-8}}$

$: \longrightarrow{\tt{p(2) =32 - 32 }}$

$\dashrightarrow{\underline{ \purple{\boxed{\bf{p( 2) = 0}}}}}$

$\huge{\red{\therefore}}$ Remainder = 0.