Question

divide x³+x²-2x +5 by x-5 and verify division algorithm​

Answer 1

Answer:

we divide f(x)=3x

3

+x

2

+2x+5 by g(x) we get q(x)=(3x−5) as quotient and r(x)=(9x+10) as remainder.

By using division algorithm,

f(x)=g(x)q(x)+r(x)

⟹3x

3

+x

2

+2x+5=g(x)(3x−5)+(9x+10)

⟹g(x)=

(3x−5)

3x

3

+x

2

+2x+5−9x−10

⟹g(x)=

(3x−5)

3x

3

+x

2

−7x−5

Hence, g(x)=x

2

+2x+1

Answer 2

Answer:

x-5) x³+x²-2x+5 (x²+6x+28

x³-5x²

___-__+______

6x²-2x

6x²-30x

_____-___+___

28x+5

28x-140

________-___+_____

145

Step-by-step explanation:

x-5=0

x=5

now,

5³+5²-2×5+5

125+25-10+5

155-10

145