Question

Divide y^3 - 125 by y - 5. please answer please and don't spam the answer of this question is y^2+5y+25 please answer​

Answer 1

Step-by-step explanation:

(y³ - 125)=y³-(5³)

by applying the formula a³-b³= (a-b)(a²+ab+b²)

here let a= y and b=5

we get,

y³-(5³)=( y - 5) (y²+5y+25)----------(1)

Now divide equation 1 by y-5

we get,

y³-(5³)/(y - 5)=( y - 5) (y²+5y+25)/(y-5)

=y²+5y+25

Answer 2

ANSWER.

• Quotient: y² + 5y + 25
• Remainder: 0

SOLUTION.

By division method, we can find out the quotient and remainder.

y - 5) y³          -  125 ( y² + 5y + 25

        y³ - 5y²

      –    +

–––––––––––––––––––––

               5y²           - 125

               5y² - 25y

              –     +

–––––––––––––––––––––

                        25y - 125

                        25y - 125

                      –       +

–––––––––––––––––––––

                                0

Therefore,

→ Quotient = y² + 5y + 25

→ Remainder = 0