Question

Divide Y(5y^2–80) by 5y(y + 4)

Answer 1

This is my answer.

Plz mark it as brainliest

Answer 2

We have to divide y(5y² - 80) by 5y(y + 4)

solution : 1st method : dividend = y(5y² - 80)

= y × 5(y² - 16)

= 5y(y² - 4²)

= 5y{(y - 4)(y + 4)} [ we know, a² - b² = (a - b)(a + b) ]

= 5y(y - 4)(y + 4)

= {(y - 4)}{5y(y + 4)}

now let's divide y(5y² - 80) by 5y(y + 4)

⇒{(y - 4)}{5y(y + 4)}/{5y(y + 4)} = (y - 4)

Therefore the quotient will be (y - 4) and remainder is 0.

2nd method :

y(5y² - 80) = 5y³ - 80y

5y(y + 4) = 5y² + 20y

5y + 20y) 5y³ - 80y(y - 4

5y³ + 20y²

__________________

-20y² - 80y

-20y² - 80y

_______________________

0

Therefore the quotient is y - 4 and remainder is 0