Question

Divide(y²+2y-3)÷(y-1)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer :

›»› (y² + 2y - 3) ÷ (y - 1) = y + 3

Given :

• (y² + 2y - 3) ÷ (y - 1)

To Divide :

• (y² + 2y - 3) ÷ (y - 1)

How To Divide?

$\begin{array}{c}\sf x-y )\; \cancel{y^2}+2y-3\;(y+3\\\sf\qquad{\cancel{y^2}-y\qquad}\qquad\;\\\underline{\quad\;\;-\;\;\;\;\;\;\;+\;\;\;\;\;\;}\quad\qquad\\\sf \cancel{3y} - 3\\\sf \underline{\qquad\quad \cancel{3y}-3\quad}\qquad\\\sf \: \: \: \: \: \: \: \: \: 0\end{array}$

Required Solution :

Let's start solving the problem and understand the steps to get our final result.

$\tt{: \implies \dfrac{ {y}^{2} + 2y - 3}{y - 1}}$

Factorize the expression,

$\tt{: \implies \dfrac{(y - 1)(y + 3)}{y - 1} }$

Seperate the common factor, y - 1,

$\tt{: \implies \dfrac{(y - 1)(y + 3)}{y - 1} }$

Do the reduction of the fraction by the common factors,

$\tt{: \implies \dfrac{y + 3}{1}}$

If a certain expression is divided by 1, the expression remains as it is,

$\bf{: \implies \underline{ \: \: \underline{ \red{ \: y + 3 \: }} \: \: }}$

║Hence, the Divide of (y² + 2y - 3) ÷ (y - 1) is y + 3.║