Math, asked by roy5060, 10 months ago

Divide(y²+2y-3)÷(y-1)​

Answers

Answered by snehitha2
3

Answer:

(y+3)

Step-by-step explanation:

(y²+2y-3)÷(y-1)

=\frac{y^2+2y-3}{y-1} \\\\ =\frac{y^2-y+3y-3}{y-1} \\\\=\frac{y(y-1)+3(y-1)}{y-1} \\\\=\frac{(y-1)(y+3)}{y-1} \\\\=y+3

Answered by saishrithajan
1

Answer:

quotient is (y+3) the remainder is zero

hint: factorise the top thing and will get (y-1)(y+3) so the answer is y+3

thanks for the points

don't forget to mark as the brilliantest

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