Question

divide y³-6y²by y-1 and verify the division algorithm​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER ::

The zero of the polynomial y-1 is given by

y - 1 = 0

= 0So

Y = 1

Let f(y) = y³- 6y²

Now by the Remainder Theorem the required Remainder is

f(1) = 1³- 6× 1² = 1 - 6 = - 5