Question

divide y3-8 by y-2 .................. ......​

Answer 1

Answer:

$\red {\frac{y^{3} - 8 }{y-2}} \green {= y^{2} + 2y + 4 }$

Step-by-step explanation:

$\frac{y^{3} - 8 }{y-2}$

$= \frac{y^{3} - 2^{3} }{y-2}$

$= \frac{(y-2)(y^{2}+y\times 2 + 2^{2}}{(y-2)}$

$\boxed { \pink { a^{3}-b^{3} = (a-b)(a^{2} + ab +b^{2})}}$

$= y^{2} + 2y + 4$

Therefore.,

$\red {\frac{y^{3} - 8 }{y-2}} \green {= y^{2} + 2y + 4 }$

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Answer 2

hey mate here is your answer,

y^3-8/y-2

first take the term y^3-8

we can write it as y^3-2^3

it is in the form of a^3-b^3

=(a-b) (a^2+b^2+ab)

a=y and 2=b

(y-2)(y^2+2^2+2y)/y-2

=y^2+4+2y

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