Question

divide2x^3+6x^2-x-1 by x^2-3

Answer 1

$\large 2x^3+6x^2-x-1 \\ \\ \\ 2x^3+6x^2-6x+5x-18+17 \\ \\ \\ 2x^3-6x+6x^2-18+5x+17 \\ \\ \\ 2x(x^2-3)+6(x^2-3)+5x+17 \\ \\ \\ (x^2-3)(2x+6)+5x+17$

Thus, divided!!!

The quotient is 2x + 6 and the remainder is 5x + 17.