divided 240 in two part in such a manner that one third of one part is 72 less than second part
Answers
Answered by
0
Answer:
126 and 114
Step-by-step explanation:
let the numbers be x and 240-x
240-x-72=x/3
168-x=x/3
504-3x=x
504=4x
x=504/4=126
so the numbers are 126 and 240-126=144
Answered by
0
step by step
let the second part is x
first part is x/3-72
240=x+(x/3-72)
240= (3x+x-216)//3.{ by taking LCM}
240*3=4x-216
4x=720+216
4x=936
x= 234
so second no is 234
first no is 234/3-72
= 78-72
= 6
hope this help
let the second part is x
first part is x/3-72
240=x+(x/3-72)
240= (3x+x-216)//3.{ by taking LCM}
240*3=4x-216
4x=720+216
4x=936
x= 234
so second no is 234
first no is 234/3-72
= 78-72
= 6
hope this help
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