Question

divided by 6 7 8 9 and 10 leaves remainder 1​

Answer 1

Given numbers,

6 , 7 , 8, 9 and 10

Prime factorization of,

6=2×3

7=1×7

8=2³

9=3²

10=5×2

LCM=product of each prime factor of highest power

LCM=2³×3²×7×5=504×5=2520

2520 is the least number exactly divisible by 6,7,8,9 and 10.

Hence,

least number which when divided by 6,7,8,9 and 10 leaves remainder 1 in each case=2520+1=2521.

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