Divided by 9, I leave a remainder of 6. Divided by 4, I leave a remainder of 1. Divided by 10, I leave a remainder of 3. Who am i?
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Therefore the number is 33.
Divided by 9, It leaves a remainder of 6. Divided by 4, It leaves a remainder of 1 and , Divided by 10, It leaves a remainder of 3.
We have to find the number.
Let the number be x.
Divided by 9, It leaves a remainder of 6.
From Euclid lemma, a = bq + r
x = 9P + 6 , where P is quotient.
Similarly.
Now, it is divided by 4 , leaves a remainder of 1.
∴ x = 4Q + 1, where Q is quotient.
Again, It is divided by 10, leaves a remainder of 3.
∴ x = 10R + 3.
∵ x = 9P + 6 = 4Q + 1 = 10R + 3
⇒ 9P + 5 = 4Q
if we choose, P = 3, Then Q = 8
Now, x = 9 × 3 + 6 = 33
Therefore the number is 33.
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