Question

divided by
Find the smallest number which when
divided by 25,40 and 60 leaves remainder 7 in each case​

Answer 1

LCM of 25, 40 and 60 is 600.

As there should be a remainder of 7, we will add 7 to 600 i.e. 607

Hence, 607 is the smallest number which when divided by 25, 40 and 60 leaves a remainder of 7 in each case.