Question

divided RS 47 between a, b,c so that a may have 10 rs more than b, and b rs 8 more than c

Answer 1

b=8+c

a=10+b=10+8+c=18+c

Now, a+b+c=47

This implies (18+c)+(8+c)+c=47

This implies 26+3c=47

This implies 3c=21

This implies c=7

c=7,b=15,a=25

Answer 2

Answer : A = 25, B = 15, C = 7

Step-by-step explanation:

Let the number of B be x

A = (x+10)

C = (x-8)

According to question

x+(x+10)+(x-8) = 47

x+x+10+x-8 = 47

x+x+x+10-8 = 47

3x+2 = 47

3x = 47-2

3x = 45

x = 45/3

x = 15

B = 15

Therefore, A = 10+15 = 25

B = 15

C = 15-8 = 7

I hope its useful for you