Math, asked by skartikey848, 1 month ago

dividend.
Which of the following has not real
roots? *
3q2 + 2q - 1 = 0
2q2 + q - 2 = 0
4q2 + 3q + 1 = 0
4q2 + 4q + 1 = 0​

Answers

Answered by pp704554
0

Answer:

3rd and 4th has not real roots.

Step-by-step explanation:

for any equation ax2 + bx + c if b2 - 4ac > 0 it contains real roots

Answered by ajb7899
0

Answer:

In order to have real roots :-

d \geqslant 0 \\ i.e. \:  {b}^{2}  - 4ac \geqslant 0

i) D = 4 - 4(3)(-1) = 16>0 Real roots

ii) D = 1 - 4(2)(-1) = 9 >0 Real roots

iii)D = 9 - 4(4)(1) = -7<0 No- real roots

iv)D = 16 - 4(4)(1) = 0 Real roots

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