dividing 2x³+ x² - 5x + 2 by x+2, the remainder is zero.
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Given, polynomial, p(x)=2x
3
+5x
2
−3x−2 divided by (x−1).
The polynomial is divided by (x−1) .
Then put (x−1)=0⟹ x=1
we get,
p(1)= 2(1)
3
+5(1)
2
−3(1)−2
⇒p(1)=2+5−3−2
⇒p(1)=2+5−5
⇒p(1)=2.
So, when p(x)= 2x
3
+5x
2
−3x−2 is divided by x−1, the remainder obtained is 2.
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