Question

Dividing a number by 2,3 and 7 in a row gives the remainder of 1,1 and 6 and the quotient is 135. What is the number? please explain...​

Answer 1

Answer:

Let the required number be x.

When this number is divided by 7 the remainder should be 6.

So the number should be in the form 7m+6 where m is a non negative integer.

Again 6 is divisible by both 2 and 3 and when 7 is divided by 2 or 3 the remainder is 1.

So the number 7m should be in the form 7(6n+1) where n= 0,1,2,3,…..

So the first number which satisfies the required condition is 7(6×0 + 1) + 6 = 13, and the next number will be 7(6×1+1) + 6 = 55 and so on.

When we divide these numbers with 42 we will get a remainder 13

Answer 2

Answer:

Let the required number be x.

When this number is divided by 7 the remainder should be 6.

So the number should be in the form 7m+6 where m is a non negative integer.

Again 6 is divisible by both 2 and 3 and when 7 is divided by 2 or 3 the remainder is 1.

So the number 7m should be in the form 7(6n+1) where n= 0,1,2,3,…..

So the first number which satisfies the required condition is 7(6×0 + 1) + 6 = 13, and the next number will be 7(6×1+1) + 6 = 55 and so on.

When we divide these numbers with 42 we will get a remainder 13