Dividing x³+4x³+4x-3 by x-1 what is the remainder
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Answer:
Remainder => 6
Step-by-step explanation:
f(x) = x³ + 4x² + 4x - 3
x - 1 = 0 => x = 1
Using remainder theorem ,
Remainder f(1) = 1³ + 4 .1² + 4 .1 - 3 = 1 + 4 + 4 - 3 = 6
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