Question

divine x^3 -3x^2+4x-3 by x-1 and check the division algorithm​

Answer 1

Answer:

Brainlist pls

Step-by-step explanation:

ur answer is there in image

Answer 2

Answer:

Quotient = x^2-2x+2 ; Remainder = -1

Step-by-step explanation:

x-1 ) x^3-3x^2+4x-3 ( x^2-2x+2

x^3(-)x^2

- +

__________________

0 -2x^2 +4x

(-)2x^2 (+)2x

+ -

___________________

0 + 2x - 3

(+) 2x(-)2

- +

____________________

0 - 1

Therefore remainder is -1

Division algorithm:-

Dividend= (Divisor*Quotient)+Remainder

x^3-3x^2+4x-3= (x-1) (x^2-2x+2) + (-1)

x^3-3x^2+4x-3= x^3-2x^2+2x-x^2+2x-2 +(-1)

x^3-3x^2+4x-3= x^3-3x^2+4x-2-1

x^3-3x^2+4x-3= x^3-3x^2+4x-3