Question

Divirte 11a²b³(7c-35)÷3a²b²(6-8)​

Answer 1

Step-by-step explanation:

Solution :

11 a^2 b^3 × (7c - 35)

-------------------------------

3a^2 b^2 × (6 - 8)

.'. Putting 7(c-5) in place of (7c - 35) and dividing a³b³ by a²b²

We get,

11 ab × 7 (c - 35)

-------------------------

3 (c - 5)

77ab

.'. -------

3

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