Math, asked by ns0722230, 12 days ago

divisibility rule of 3, 4, 5, 6, 8​

Answers

Answered by hgirl4986
1

Answer:

Divisibility rule for 3 states that a number is completely divisible by 3 if the sum of its digits is divisible by 3. Consider a number, 308. To check whether 308 is divisible by 3 or not, take sum of the digits (i.e. 3+0+8= 11). ... If the sum is a multiple of 3, then the original number is also divisible by 3.

The basic rule for divisibility by 4 is that if the number formed by the last two digits in a number is divisible by 4, the original number is divisible by 4; this is because 100 is divisible by 4 and so adding hundreds, thousands, etc. is simply adding another number that is divisible by 4.

Divisibility by 5 is easily determined by checking the last digit in the number (475), and seeing if it is either 0 or 5. If the last number is either 0 or 5, the entire number is divisible by 5. If the last digit in the number is 0, then the result will be the remaining digits multiplied by 2.

Divisibility Rule of 6

Divisibility Rule of 6That is, if the last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6. ... The sum of digits is 6+3+0 = 9, which is also divisible by 3. Hence, 630 is divisible by 6.

Divisibility Rule of 8

Divisibility Rule of 8If the last three digits of a number are divisible by 8, then the number is completely divisible by 8. ... Consider the last two digits i.e. 344. As 344 is divisible by 8, the original number 24344 is also divisible by 8.

Step-by-step explanation:

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Answered by ouk1122334455
0

Step-by-step explanation:

8=a number is divisible by 8 if the number formed by its last three digit on its extremely right is divisible by 8

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