Divisibility rules 2-11
Answers
when the last digit of a number is even then it
will divisible by 2
divisibility rule for 3
if the sum of digits of any number is a multiple of 3 then that number is divisible by 3
ex. 363 =3 + 6 +3 =12 (divisible by 3)
so it would be divisible by 3 also
divisibility rule for 4
if the last digits of a number is a multiple of 4 then that number is divisible by 4
ex. 464
64 is a multiple of 4 (4×16) so the number 464 is divisible by 4
divisibility rule for 5
if a number has either 0 or 5 in its units place then that numbet is divisible by 5
ex.970 , 675
unit place is 0 or 5 . so all the above numbers are divisible by 5
d
Step-by-step explanation:
Divisibility Rule of 1
Every number is divisible by 1. Divisibility rule for 1 doesn’t have any condition. Any number divided by 1 will give the number itself, irrespective of how large the number is. For example, 3 is divisible by 1 and 3000 is also divisible by 1 completely.
Divisibility Rule of 2
If a number is even or a number whose last digit is an even number i.e. 2,4,6,8 including 0, it is always completely divisible by 2.
Example: 508 is an even number and is divisible by 2 but 509 is not an even number, hence it is not divisible by 2. Procedure to check whether 508 is divisible by 2 or not is as follows:
Consider the number 508
Just take the last digit 8 and divide it by 2
If the last digit 8 is divisible by 2 then the number 508 is also divisible by 2.
Divisibility Rules for 3
Divisibility rule for 3 states that a number is completely divisible by 3 if the sum of its digits is divisible by 3.
Consider a number, 308. To check whether 308 is divisible by 3 or not, take sum of the digits (i.e. 3+0+8= 11). Now check whether the sum is divisible by 3 or not. If the sum is a multiple of 3, then the original number is also divisible by 3. Here, since 11 is not divisible by 3, 308 is also not divisible by 3.
Similarly, 516 is divisible by 3 completely as the sum of its digits i.e. 5+1+6=12, is a multiple of 3.
Divisibility Rule of 4
If the last two digits of a number are divisible by 4, then that number is a multiple of 4 and is divisible by 4 completely.
Example: Take the number 2308. Consider the last two digits i.e. 08. As 08 is divisible by 4, the original number 2308 is also divisible by 4.
Divisibility Rule of 5
Numbers, which last with digits, 0 or 5 are always divisible by 5.
Example: 10, 10000, 10000005, 595, 396524850, etc.
Divisibility Rule of 6
Numbers which are divisible by both 2 and 3 are divisible by 6. That is, if the last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6.
Example: 630, the number is divisible by 2 as the last digit is 0.
The sum of digits is 6+3+0 = 9, which is also divisible by 3.
Hence, 630 is divisible by 6.
Divisibility Rules for 7
The rule for divisibility by 7 is a bit complicated which can be understood by the steps given below:
Divisibility rule of 7
Example: Is 1073 divisible by 7?
From the rule stated remove 3 from the number and double it, which becomes 6.
Remaining number becomes 107, so 107-6 = 101.
Repeating the process one more time, we have 1 x 2 = 2.
Remaining number 10 – 2 = 8.
As 8 is not divisible by 7, hence the number 1073 is not divisible by 7.
Divisibility Rule of 8
If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.
Example: Take number 24344. Consider the last two digits i.e. 344. As 344 is divisible by 8, the original number 24344 is also divisible by 8.
Divisibility Rule of 9
The rule for divisibility by 9 is similar to divisibility rule for 3. That is, if the sum of digits of the number is divisible by 9, then the number itself is divisible by 9.
Example: Consider 78532, as the sum of its digits (7+8+5+3+2) is 25, which is not divisible by 9, hence 78532 is not divisible by 9.
Divisibility Rule of 10
Divisibility rule for 10 states that any number whose last digit is 0, is divisible by 10.
Example: 10, 20, 30, 1000, 5000, 60000, etc.
Divisibility Rules for 11
If the difference of the sum of alternative digits of a number is divisible by 11, then that number is divisible by 11 completely.
In order to check whether a number like 2143 is divisible by 11, below is the following procedure.
Group the alternative digits i.e. digits which are in odd places together and digits in even places together. Here 24 and 13 are two groups.
Take the sum of the digits of each group i.e. 2+4=6 and 1+3= 4
Now find the difference of the sums; 6-4=2
If the difference is divisible by 11, then the original number is also divisible by 11. Here 2 is the difference which is not divisible by 11.
Therefore, 2143 is not divisible by 11.
A few more conditions are there to test the divisibility of a number by 11. They are explained here with the help of examples:
If the number of digits of a number is even, then add the first digit and subtract the last digit from the rest of the number.
Example: 3784
Number of digits = 4
Now, 78 + 3 – 4 = 77 = 7 × 11
Thus, 3784 is divisible by 11.
If the number of digits of a number is odd, then subtract the first and the last digits from the rest of the number.
Example: 82907
Number of digits = 5
Now, 290 – 8 – 7 = 275 × 11
Thus, 82907 is divisible by 11