Question

divisibility rules of 1,2,3,4,5,6,7,8,9,10 and 11​

Answer 1

Answer:

1- All the numbers are divisible by 1

2- Numbers with 2,4,6,8, or 0 in the one's place

3-Sum of all digits should be divisible by 3

4-Last two digits of the number should be divisible by 4

5-Numbers that have 0 or 5 in the one's place are divisible by 5

6-The number must be divisible by both 2 and 3

8-Last three digits of the number must be divisible by 8

9-Sum of all the digits should be divisible by 9

10-Any number that has 0 in the ones place is divisible by 10

11-The difference of the sum of odd "places" and even "places" must be divisible by 11

Step-by-step explanation:

In case of 11, the places are as follows. It starts from the one's place as an odd place.

Example:

Check whether 605 is divisible by 11

Ans: 6. 0. 5

Odd. Even. Odd

so the sum of numbers in odd place=6+5

=11

Sum of numbers in even place= 0

difference

11-0=11

Therefore, 605 is divisible by 11.