Question

divisibility rules of number 2,3,4,5,6,8,9,and11 Explain with 2 explain each

















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Answer 1

Rule for 2:-
The last digit (ones place), must be 0,2,4,6 or 8.

Rule for 3 and 9:-
The sum of all digits must be a multiple of 3.
39 = 3+9 = 12.
Multiple of 3.

The sum of all digits must be a multiple of 9.
90 = 9+0 = 9.
Multiple of 9.

Rule for 4 and 8:-
The last two digits of the number must be divisible by 4 or can be 0. Then it’s divisible by 4.

Rule for 4 and 8:-
The last three digits of the number must be divisible by 8 or can be 0. Then it’s divisible by 8.

Rule for 5:-
The last digit (ones place) must be 0 or 5.

Rule for 6:-
The number must be divisible by 2 and 3 both! Then it’s divisible by 6.

Rule for 11:-
The difference of the sum of even places and difference of the sum of odd places of that number must be either multiple of 11 or be 0.


132

Even places = 3
Odd places = 1 + 2
= 3 - 3 = 0

Divisible by 11.


All the rules.