divisibility test of 2, 3, 7, 8 with suitable example
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3
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Here's your best answer =>>>
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# Divisibility Test of 2 :
If the last digits have the unit place as 2,4,6,8... so we can tell, that's number divisible by 2.
# Divisibility test of 3 :
The sum of all digits equals to numbers equal to multiple by 3. it can be said as divisible by 3.
# Divisibility test of 7 :
Double the last digit and subtract it from the remaining leading truncated number, so the number is divisible by 7.
# Divisibility test of 8 :
If the last three digits are divided by 8 i.e. of whole number, said as divisible by 8.
====================================
I'm EXPERT: no4.
Hope it helps u :)
MARK ME AS BRAINLIEST PLZ PLZ PLZ. . .
Here's your best answer =>>>
====================================
# Divisibility Test of 2 :
If the last digits have the unit place as 2,4,6,8... so we can tell, that's number divisible by 2.
# Divisibility test of 3 :
The sum of all digits equals to numbers equal to multiple by 3. it can be said as divisible by 3.
# Divisibility test of 7 :
Double the last digit and subtract it from the remaining leading truncated number, so the number is divisible by 7.
# Divisibility test of 8 :
If the last three digits are divided by 8 i.e. of whole number, said as divisible by 8.
====================================
I'm EXPERT: no4.
Hope it helps u :)
MARK ME AS BRAINLIEST PLZ PLZ PLZ. . .
Answered by
2
For 2
if the last digit n of is 2, 4, 6, 8, or 0;
For 3
if the sum of digits of n is a multiple of 3;
For 7
if subtracting twice the last digit of n from the remaining digits gives a multiple of 7
For 8
if the last 3 digits of n are a multiple of 8
if the last digit n of is 2, 4, 6, 8, or 0;
For 3
if the sum of digits of n is a multiple of 3;
For 7
if subtracting twice the last digit of n from the remaining digits gives a multiple of 7
For 8
if the last 3 digits of n are a multiple of 8
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