Math, asked by vidyasagarmall404, 2 months ago

divisible by 3
(a)2040
(b)6395
(c)9604
(d)3692​

Answers

Answered by varunolimattel
0

Answer:

2040

Step-by-step explanation:

Divisibility test for 3 - all digits should add up to a factor of 3. In this case, only 2+0+4+0=6=3x2.

Answered by IntrovertLeo
11

Given:

Four numbers -

  • a. 2040
  • b. 6395
  • c. 9604
  • d. 3692

What To Find:

We have to find that

  • Whether the given four numbers are divisible by 3.

How To Find:

To find it, we have to

  • First, find the sum of the digits.
  • Next, find out whether the number is multiple of 3.
  • If yes, then it is divisible by 3.
  • If no, then it is not divisible by 3.

Solution:

  • a. 2040

Sum of the given digits,

⇒ 2 + 0 + 4 + 0

Add the digits,

⇒ 6

Check whether it is multiple of 3,

⇒ Yes, it is.

∴ Hence, 2040 is divisible by 3.

  • b. 6395

Sum of the given digits,

⇒ 6 + 3 + 9 + 5

Add the digits,

⇒ 23

Check whether it is multiple of 3,

⇒ No, it isn't.

∴ Hence, 6395 is not divisible by 3.

  • c. 9604

Sum of the given digits,

⇒ 9 + 6 + 0 + 4

Add the digits,

⇒ 19

Check whether it is multiple of 3,

⇒ No, it isn't.

∴ Hence, 9604 is not divisible by 3.

  • d. 3692

Sum of the given digits,

⇒ 3 + 6 + 9 + 2

Add the digits,

⇒ 20

Check whether it is multiple of 3,

⇒ No, it isn't.

∴ Hence, 3692 is not divisible by 3.

Final Answer:

a. 2040 is divisible by 3.

b. 6395 is not divisible by 3.

c. 9604 is not divisible by 3.

d. 3692 is not divisible by 3.

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