Math, asked by santoshgupta5378, 1 year ago

divisible by 7 karna hai

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Answered by RohitSaketi
3
Divisibility rule of 7... multiply the last digit of the number with 2..and subtract this from earlier digits..if the result is divisible by 7 or 0..then The number will also be divisible by 7..

1)3132 = 313 - (2×2) = 313 - 4 = 309

309 = 30 -(2×9) = 12 is not divisible by 7 ..so 3132 is also not divisible by 7..

2)5704 = 570 - (2×4) = 570 - 8= 562

562 = 56 -(2×2) = 52 is not divisible by 7 so..5704 is Also not divisible by 7.

3)8316 = 831 - (2×6) = 831 - 12 = 819
819 = 81 - (2×9) = 63 is divisible by 7. (7 ×9 =63) .so 8316 is also divisible by 7

4)7038 = 703 - {2×8) = 703 - 16 = 687

687 = 68 -(2×7) = 54 is not divisible by 7..so 7038 is also not divisible by 7.

5)3045 = 304 - (2×5) = 294

294 = 29 - (2×4) = 29 - 8 = 21 is divisible by 7 (7×3 =21) ..so 3045 is also divisible by 7.

6)7833 = 783 - (2×3) = 777
777=77 - (2×7) = 63 (7×9=63) is divisible by 7 so 7833 is divisible by 7
Answered by sahooakhilakumar721
0

Answer:

The number that have ones place digit is multiple of 2 And Subtract the rest number. That number is divisible 7 .

Ex - a) 6895

Now, 689-(2×5) =(689-10) =679,Which is divisible by 7.

Therefore,6895 is divisible by 7.

Ex -b) 727

Now ,72 -(2×7)=(72-14)=58,Which is not divisible by 7.

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